(x^2-1)(0.6x+1)=0.6x^2+x

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Solution for (x^2-1)(0.6x+1)=0.6x^2+x equation: 



(x^2-1)(0.6x+1)=0.6x^2+x

We move all terms to the left:

(x^2-1)(0.6x+1)-(0.6x^2+x)=0

We get rid of parentheses

-0.6x^2+(x^2-1)(0.6x+1)-x=0

We add all the numbers together, and all the variables

-0.6x^2-1x+(x^2-1)(0.6x+1)=0

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